**Description **

Diophantus of Alexandria was an Egypt mathematician living in Alexandria. He
was one of the first mathematicians to study equations where variables were
restricted to integral values. In honor of him, these equations are commonly
called Diophantine equations. One of the most famous Diophantine equation is
xn + yn = zn. Fermat suggested that for n > 2, there are no solutions with
positive integral values for x, y and z. A proof of this theorem (called Fermat¡¯s
last theorem) was found only recently by Andrew Wiles.

Consider the following Diophantine equation:

Diophantus is interested in the following question: for a given n, how many distinct solutions (i. e., solutions satisfying x ¡Ü y) does equation (1) have? For example, for n = 4, there are exactly three distinct solutions:

Clearly, enumerating these solutions can become tedious for bigger
values of n. Can you help Diophantus compute the number of distinct solutions
for big values of n quickly?

**Input**

The first line contains the number of scenarios. Each scenario consists of one
line containing a single number n (1 ¡Ü n ¡Ü 10^9).

**Output**

The output for every scenario begins with a line containing ¡°Scenario #i:¡±,
where i is the number of the scenario starting at 1. Next, print a single line
with the number of distinct solutions of equation (1) for the given value of
n. Terminate each scenario with a blank line.

**Sample Input
**

2

4

1260

**Sample Output
**

Scenario #1:

3

Scenario #2:

113

**Source**

TUD Programming Contest 2006, Darmstadt, Germany