```Description

You are the boss of a small lighting fixture company which has n employees.
Inspired by Ben Stiller¡¯s character in Starsky and Hutch, you have recently
taken on the habit of telling your employees to ¡°do it!¡± when you want things
done. While n+ of the n employees respond positively to your ¡°do it!¡±s, n?
employees respond negatively and n0 are neutral to your words.

At time 0, each of your employees begins working alone on building a lighting
fixture. Each lighting fixture takes 100 units of labor to finish. Normally,
each of your employees contributes r units of labor towards finishing his/her
lighting fixture during each time interval (or the amount of labor units remaining
for the fixture, whichever is smaller). Thus, an employee would normally take
ceiling(100 ? r) time intervals to finish his or her lighting fixture. During
an interval, however, if you yell ¡°do it!¡± over the company intercom, employees
who respond positively to your command will do r + 2 units of labor during that
time interval, whereas employees who respond negatively will do r ? 1 units of
labor during the time interval.

Assuming that each employee works on only his or her lighting fixture, and assuming
that you yell ¡°do it!¡± at most once during each time interval, your goal is to
plan a sequence of ¡°do it!¡±s so as to ensure that the sum of the times needed
to finish all n lighting fixtures is minimized.

Input

The input test file will contain multiple test cases. Each input test case will
be given as a line containing four integers, n+, n?, n0, and r
(where 0 ¡Ü n+, n?, n0 ¡Ü 1000 and 1 ¡Ü r ¡Ü 100). The end-of-file is marked by
a test case with n+ = n? = n0 = r = 0 and should not be processed.

Output

For each input case, the program should print the minimum sum of times needed to
finish all n lighting fixtures.

Sample Input

3 1 1 2
1 3 0 2
0 0 0 0

Sample Output

188
200

Hint

In first test case, one optimal strategy is to yell ¡°do it¡± in each of the first
25 time intervals. As a result, the 3 positively-responding employees provide 4
units of labor per time interval and thus finish their fixtures in 25 time units.
The 1 negatively-responding employee will provide 1 unit of labor per time interval
for the first 25 time intervals, 2 units of labor per time interval afterwards, and
thus will finish in 25 + 38 = 63 time units. Finally, the neutral employee will
always provide 2 units of labor per time interval and hence will finish in 50 time
units. This gives a total of 3(25) + 63 + 50 = 188 time units.

In the second test case, an optimal strategy is to never yell ¡°do it¡±. Thus all
four employees finish in 50 time units so the total amount of time taken is 200
time units.

Source

Stanford Local 2005
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